5. A72 kg pole -vaulter running at 8.4m/s completes a vault. If all of her kinetic energy is transformed into potential energy, what is the maximum height of her vault?

Question

5. A72 kg pole -vaulter running at 8.4m/s completes a vault. If all of her kinetic energy is transformed into potential energy, what is the maximum height of her vault?

Answer 1

Here's how to solve this problem:**1. Understand the principle:**The problem states that all kinetic energy is converted into potential energy. This means we can use the following equation:Kinetic Energy (KE) = Potential Energy (PE)**2. Write down the formulas:*** KE = (1/2) * m * v² , where m is mass and v is velocity* PE = m * g * h, where m is mass, g is acceleration due to gravity (approximately 9.8 m/s²), and h is height.**3. Set up the equation:**(1/2) * m * v² = m * g * h**4. Solve for height (h):**Notice that the mass (m) appears on both sides of the equation, so we can cancel it out:(1/2) * v² = g * hNow, isolate h:h = (v²) / (2 * g)**5. Plug in the values:**h = (8.4 m/s)² / (2 * 9.8 m/s²)**6. Calculate:**h = 70.56 m²/s² / 19.6 m/s²h ≈ 3.6 m**Answer:** The maximum height of her vault is approximately 3.6 meters.

Question

5. A72 kg pole -vaulter running at 8.4m/s completes a vault. If all of her kinetic energy is transformed into potential energy, what is the maximum height of her vault?

Solution

Answer