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Question 12 Rewrite X^2+8x-7 in the Form (x-h)^2+k by Completing the Square. (x-4)^2+23 (x+4)^2+23 (x+4)^2-23 (x-4)^2-23

Question

Question 12 Rewrite x^2+8x-7 in the form (x-h)^2+k by completing the square. (x-4)^2+23 (x+4)^2+23 (x+4)^2-23 (x-4)^2-23

Solution

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Answer

### C.

Explanation

## Step 1: Group the terms### Isolate the terms with . ## Step 2: Complete the square for the terms### To complete the square for , take half of the coefficient of the term (which is 8), square it , and add and subtract it inside the parenthesis. ## Step 3: Rewrite the perfect square trinomial### The expression is a perfect square trinomial and can be factored as . So, ## Step 4: Simplify the constant terms### Combine the constant terms: . Thus, .