4. An object is experiencing an acceleration of 3.0m/s^2 while traveling in a circle at a velocity of 18.0m/s What is the radius of its motion? Formula

The formula that relates centripetal acceleration (a), velocity (v), and radius (r) of circular motion is:a = v²/rWe are given:* a = 3.0 m/s²* v = 18.0 m/sWe need to solve for r:1. **Rearrange the formula:** r = v²/a2. **Substitute the given values:** r = (18.0 m/s)² / (3.0 m/s²)3. **Calculate:** r = 324 m²/s² / 3.0 m/s² = 108 mTherefore, the radius of the circular motion is .