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1. A Box Is Lifted off the Ground Using a Net Force of 8.1times 10^2N[up]. The Box Has an Average Acceleration of 3.1m/s^2 [up]. A.

Question

1. A box is lifted off the ground using a net force of 8.1times 10^2N[up]. The box has an average acceleration of 3.1m/s^2 [up]. a. Calculate the mass of the box. (3) b. Calculate the weight of the box.(2)

Solution

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Answer

**1.a. Calculating the Mass of the Box*** **Known:** * Net Force (Fnet) = 8.1 x 10² N [up] * Acceleration (a) = 3.1 m/s² [up]* **Formula:** Newton's Second Law of Motion states that Fnet = ma, where m is the mass.* **Calculation:** * Rearrange the formula to solve for mass: m = Fnet / a * Substitute the known values: m = (8.1 x 10² N) / (3.1 m/s²) * Calculate: m ≈ 261.29 kg* **Answer:** The mass of the box is approximately 260 kg. (Rounded to two significant figures as per the given data's precision.)**1.b. Calculating the Weight of the Box*** **Known:** * Mass (m) = 261.29 kg (We'll use the unrounded value for greater accuracy in this step, then round the final answer) * Acceleration due to gravity (g) = 9.81 m/s² (Standard value on Earth)* **Formula:** Weight (W) is the force of gravity acting on an object and is calculated as W = mg.* **Calculation:** * Substitute the known values: W = (261.29 kg) * (9.81 m/s²) * Calculate: W ≈ 2563.26 N* **Answer:** The weight of the box is approximately 2.6 x 10³ N. (Rounded to two significant figures)