7. Tyler rows 10 km downstream in 2 h. On the return trip, it takes him 4 h to travel 8 km . Determine his average rowing speed and the speed of the current.

Here's how to solve this problem:**1. Define Variables:*** Let 'r' be Tyler's rowing speed in still water (km/h).* Let 'c' be the speed of the current (km/h).**2. Set up Equations:*** **Downstream:** When rowing downstream, the current *adds* to Tyler's speed. The distance is 10 km and the time is 2 hours. So, the equation is: r + c = 10/2 or r + c = 5* **Upstream:** When rowing upstream, the current *subtracts* from Tyler's speed. The distance is 8 km and the time is 4 hours. So, the equation is: r - c = 8/4 or r - c = 2**3. Solve the System of Equations:**We have two equations with two unknowns:* r + c = 5* r - c = 2The easiest way to solve this is using elimination. Add the two equations together:(r + c) + (r - c) = 5 + 2This simplifies to:2r = 7Therefore:r = 7/2 = 3.5 km/hNow substitute this value of 'r' back into either of the original equations. Let's use the first one:3.5 + c = 5c = 5 - 3.5c = 1.5 km/h**4. Determine Average Rowing Speed:**Tyler's average rowing speed is his speed in still water, which we calculated as 3.5 km/h.**Answer:**Tyler's average rowing speed is 3.5 km/h, and the speed of the current is 1.5 km/h.