Use the following information to answer the question. In an experiment, a researcher studied the decay of (}^210_{84)PO , which decays by alpha emission and releases a stable (}^206_(82)Pb atom. The half-life of ()^210_{84)Po is 138.4 days.The mass of the sample of (}^210_{84) Po at the start of the experiment was 34.0 g. Numerical Response 6. The amount of {}^21084 Po remaining after 415.2 days was __ g.

Here's how to calculate the amount of Polonium-210 remaining after 415.2 days:1. **Determine the number of half-lives:** * Time elapsed: 415.2 days * Half-life of Po-210: 138.4 days * Number of half-lives = Time elapsed / Half-life = 415.2 days / 138.4 days = 32. **Calculate the remaining amount:** * Initial mass: 34.0 g * After 1 half-life: 34.0 g * (1/2) = 17.0 g * After 2 half-lives: 17.0 g * (1/2) = 8.5 g * After 3 half-lives: 8.5 g * (1/2) = 4.25 gTherefore, the amount of Po remaining after 415.2 days is g.