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A Women of Blood Type AB (1^Avert ^B) Has a Child with a Man of Blood Type AB ( ") as Well. What Are the Chances of the First Child

Question

A women of blood type AB (1^Avert ^B) has a child with a man of blood type AB ( ") as well. What are the chances of the first child being blood type B? What are the chances of blood type O? 25% ,25% 100% ,0% 25% ,0% 0% ,0% 50% ,50%

Solution

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Answer

Here's how to determine the blood type probabilities for the child:**Understanding Blood Type Inheritance*** **A and B are codominant:** If someone has both A and B alleles, they have blood type AB.* **O is recessive:** Someone needs two O alleles to have blood type O.**Parent Genotypes*** Mother: AB (IAIB)* Father: AB (IAIB)**Punnett Square**A Punnett square helps visualize the possible combinations of alleles the child can inherit:| | IA | IB ||-------|--------|--------|| IA | IAIA | IAIB || IB | IAIB | IBIB |**Possible Child Genotypes and Phenotypes (Blood Types)*** IAIA: Blood type A* IAIB: Blood type AB* IBIB: Blood type B**Probabilities*** **Blood type A:** 1 out of 4 possibilities (25%)* **Blood type AB:** 2 out of 4 possibilities (50%)* **Blood type B:** 1 out of 4 possibilities (25%)* **Blood type O:** 0 out of 4 possibilities (0%)**Answer**The correct answer is . There is a 25% chance the child will have blood type B and a 0% chance the child will have blood type O.