Question
so Two students are sitting 1.3 meters apart. One student has a mass of 62 kg. If the gravitational force between the two students is 1.08times 10^wedge 8 Newtons, what is the mass of the other student? Type square countries
Solution
4.4
(178 Votes)
David
Elite · Tutor for 8 years
Answer
Here's how to solve this problem using Newton's Law of Universal Gravitation:**1. The Formula:**Newton's Law of Universal Gravitation states:F = G * (m1 * m2) / r^2Where:* F is the gravitational force* G is the gravitational constant (6.674 x 10^-11 N⋅m²/kg²)* m1 and m2 are the masses of the two objects* r is the distance between the centers of the two objects**2. Plug in the known values:**We know:* F = 1.08 x 10^-8 N* G = 6.674 x 10^-11 N⋅m²/kg²* m1 = 62 kg* r = 1.3 mWe want to find m2.**3. Rearrange the formula to solve for m2:**m2 = (F * r^2) / (G * m1)**4. Calculate m2:**m2 = (1.08 x 10^-8 N * (1.3 m)^2) / (6.674 x 10^-11 N⋅m²/kg² * 62 kg)m2 ≈ 44.9 kg**Answer:** The mass of the other student is approximately 44.9 kg.