Elaine shoots a bullet straight up in the air from a gún.It reaches a height of 1940 m. How fast was the bullet fired?

Here's how to solve this problem using the principles of physics:**1. Understand the Concepts*** **Free Fall:** When the bullet reaches its maximum height, its velocity becomes zero just before it starts falling back down. We can treat this upward journey as a case of uniform deceleration due to gravity.* **Equations of Motion:** We'll use the following equation of motion: v² = u² + 2as Where: * v = final velocity (0 m/s at the highest point) * u = initial velocity (what we want to find) * a = acceleration (in this case, -9.8 m/s² due to gravity, negative since it's acting downwards) * s = displacement (1940 m)**2. Solve for Initial Velocity (u)*** Substitute the known values into the equation: 0² = u² + 2 * (-9.8 m/s²) * 1940 m* Simplify and solve for u: 0 = u² - 38024 m²/s² u² = 38024 m²/s² u = √38024 m²/s² u ≈ 195 m/s**Answer:** The bullet was fired at approximately 195 m/s.