Question 26 (1 point) The heat transferred when 250 g of water at 98 degrees Celsius cools to room temperature at 20.0 degrees Celsius is __ in an __ process 6.47times 10^5 J. exothermic 8.17times 10^4 , exothermic 6.47times 10^5 J, endothermic 8.17times 10^4 , endothermic

The heat transferred when 250 g of water at 98 degrees Celsius cools to room temperature at 20.0 degrees Celsius is in an process.**Explanation:**1. **Calculate the change in temperature:** ΔT = T_final - T_initial = 20.0°C - 98°C = -78°C2. **Convert mass to kilograms:** m = 250 g = 0.250 kg3. **Use the specific heat capacity of water:** The specific heat capacity of water (c) is 4.184 J/g°C or 4184 J/kg°C.4. **Calculate the heat transfer (q) using the formula:** q = mcΔT q = (0.250 kg)(4184 J/kg°C)(-78°C) q = -81732 J q ≈ -8.17 x 10⁴ J5. **Interpret the sign:** The negative sign indicates that heat is being *released* by the water, meaning the process is exothermic. Heat flows out of the system (the water) and into the surroundings.