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H=-5(k-3)^2+47 -5(t-3)^2+47=20

Question

h=-5(k-3)^2+47 -5(t-3)^2+47=20

Solution

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Adam Master ยท Tutor for 5 years

Answer

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Explanation

## Step 1: Isolate the squared term### Subtract 47 from both sides of the equation . ## Step 2: Divide by the coefficient of the squared term### Divide both sides by -5. ## Step 3: Take the square root of both sides### Take the square root of both sides. Remember to consider both positive and negative roots. ## Step 4: Simplify the square root### Simplify the square root. ## Step 5: Isolate t### Add 3 to both sides.