A mass of 0.65 kg extends a spring by 12 cm. Calculate the constant. m^-1 0.054Nm^-1 53.08Nm^-1 0.55

Here's how to calculate the spring constant:**1. Understand the concept:**Hooke's Law states that the force exerted by a spring is proportional to its extension (or compression). Mathematically, this is represented as:F = kxWhere:* F is the force applied (in Newtons)* k is the spring constant (in Newtons per meter, Nm⁻¹)* x is the extension (or compression) of the spring (in meters)**2. Identify the knowns:*** m (mass) = 0.65 kg* x (extension) = 12 cm = 0.12 m (Important: convert cm to meters)* g (acceleration due to gravity) = 9.8 m/s² (We need this because the weight of the mass is the force extending the spring)**3. Calculate the force:**The force extending the spring is the weight of the mass:F = mg = (0.65 kg)(9.8 m/s²) = 6.37 N**4. Solve for the spring constant (k):**Rearrange Hooke's Law to solve for k:k = F/x = 6.37 N / 0.12 m = 53.08 Nm⁻¹**Therefore, the spring constant is 53.08 Nm⁻¹.**