4. Cam applies a horizontal force of 80.0 N on Vishwa as he sits on a sled. They have a combined mass of 85.0 kg.Vishwa accelerates at 0.090m/s^2 and there is some friction. a. Draw a free-body diagram. Label all forces and their relation to each other. b. What is the net force (F_(net)) on Vishwa and the sled? /1 c. What is the force of friction in this case d. What is the coefficient of kinetic friction? /1 5. Jessilyn is using 50.0 N of force, acting 32^circ up from the horizontal to pull a toboggan and passenger with total mass of 55.0 kg along a level snow couorod curface The

**4.****(a) Free-Body Diagram:**[asy]unitsize(0.5 cm);pair A, B, C, D;A = (0,0);B = (5,0);C = (5,2);D = (0,2);draw(A--B--C--D--cycle);draw(A+(1,1)--(A+(2,1),Arrow(6));label(" N", A+(1.5,1), S);draw(A+(3.5,1)--(A+(2.5,1),Arrow(6));label(" ", A+(3,1), S);draw(A+(2.5,2.5)--(A+(2.5,1.5),Arrow(6));label(" ", A+(2.5,2), N);draw(A+(2.5,0.5)--(A+(2.5,-0.5),Arrow(6));label(" ", A+(2.5,0), S);label("Vishwa & Sled", (2.5,1));[/asy]* **Fapplied:** The horizontal force Cam applies.* **Ffriction:** The force of friction opposing the motion.* **Fnormal:** The normal force perpendicular to the surface.* **Fgravity:** The force of gravity acting downwards.**(b) Net Force (Fnet):**Fnet = m*a Fnet = (85.0 kg) * (0.090 m/s²)Fnet = 7.65 N**(c) Force of Friction:**Fnet = Fapplied - FfrictionFfriction = Fapplied - FnetFfriction = 80.0 N - 7.65 NFfriction = 72.35 N (approximately 72.4 N)**(d) Coefficient of Kinetic Friction (μk):**Ffriction = μk * FnormalSince the sled is on a level surface, Fnormal = Fgravity = m*gFnormal = (85.0 kg) * (9.81 m/s²) = 833.85 Nμk = Ffriction / Fnormalμk = 72.35 N / 833.85 Nμk = 0.0868 (approximately 0.087)**5.** The question is incomplete. It sets up a scenario with Jessilyn pulling a toboggan but doesn't ask a specific question. To answer it, I need the rest of the problem. For example, it might ask for the acceleration of the toboggan, the force of friction, or the coefficient of friction. Please provide the complete question.