6. A woman, driving a golf ball off a tee gives the ball a speed of 38m/s The mass of the ball is 0.045 kg, and the duration of the impact with the golf club is 6times 10^-3 seconds. a. What is the change in momentum of the ball? b. Determine the force applied by the club.

**a. Change in Momentum:*** **Initial momentum:** Before being hit, the golf ball is at rest, so its initial momentum is 0 kg⋅m/s.* **Final momentum:** After being hit, the ball's momentum is calculated using the formula: momentum = mass × velocity. So, final momentum = (0.045 kg) × (38 m/s) = 1.71 kg⋅m/s.* **Change in momentum:** The change in momentum is the final momentum minus the initial momentum: 1.71 kg⋅m/s - 0 kg⋅m/s = 1.71 kg⋅m/s.**Answer:** The change in momentum of the ball is 1.71 kg⋅m/s.**b. Force Applied by the Club:*** We can use the impulse-momentum theorem, which states that the impulse (force multiplied by the time the force is applied) is equal to the change in momentum. The formula is: Impulse = Force × time = change in momentum.* We know the change in momentum (1.71 kg⋅m/s) and the time of impact ( s). We can rearrange the formula to solve for force: Force = change in momentum / time* Force = (1.71 kg⋅m/s) / ( s) = 285 N**Answer:** The force applied by the club is 285 N.