The energy needed to melt 350 g of ice which is at 0.0^circ C is __ kJ.

Here's how to calculate the energy needed to melt the ice:1. **Find the latent heat of fusion for water:** The latent heat of fusion (Lf) for water is 334 J/g. This means it takes 334 joules of energy to melt 1 gram of ice at 0°C.2. **Calculate the total energy needed:** Multiply the mass of the ice by the latent heat of fusion: Energy = mass × Lf Energy = 350 g × 334 J/g Energy = 116900 J3. **Convert joules to kilojoules:** Since the question asks for the answer in kJ, divide the energy in joules by 1000: Energy = 116900 J / 1000 J/kJ Energy = 116.9 kJTherefore, the energy needed to melt 350 g of ice at 0.0°C is kJ.