2. A2.0 kg wood box is sitting on a level steel surface. A student pushes the box and it accelerates from rest to 12.4m/s in 3.60 s. What is the net force that acting on the box? (4)

Here's how to calculate the net force acting on the wooden box:1. **Find the acceleration:**Acceleration (a) is the change in velocity (Δv) divided by the change in time (Δt).* Δv = Final velocity - Initial velocity = 12.4 m/s - 0 m/s = 12.4 m/s* Δt = 3.60 sa = Δv / Δt = 12.4 m/s / 3.60 s = 3.44 m/s²2. **Calculate the net force:**Newton's second law of motion states that force (F) equals mass (m) times acceleration (a).* m = 2.0 kg* a = 3.44 m/s²F = m * a = 2.0 kg * 3.44 m/s² = 6.88 NTherefore, the net force acting on the box is approximately