A student solved the equation x^2-6x+6=0 by completing the square. Move numbers to the lines to complete the student's calculation. x^2-6x+6=0 (x^2-6x+underline ( ))+underline ( )+6=0 (x-3)^2=underline ( ) x-3=pm underline ( ) x=underline ( )+underline ( ) and x x=underline ( )+underline ( ) -9 -6 -3

To complete the square for the equation , we need to find a number to fill in the square that makes the left side a perfect square trinomial.The equation is .Step 1: Take half of the coefficient of , which is , and square it. This gives us \((-3)^2 = 9\).Step 2: Add and subtract this number inside the parentheses to complete the square. Step 3: Solve for by taking the square root of both sides. Step 4: Solve for the two possible values of . So the completed calculation is: Therefore, the numbers that fill in the blanks are: And the solutions are: