12. Complete the following calculations, showing ALL UNITS AND ALL FIVE STEPS. a. A light bulb passes through a current of 0.7 A when the potential difference across the bulb is 60 V. What is the resistance of the bulb in ohms?

Question

12. Complete the following calculations, showing ALL UNITS AND ALL FIVE STEPS. a. A light bulb passes through a current of 0.7 A when the potential difference across the bulb is 60 V. What is the resistance of the bulb in ohms?

Answer 1

Here's the solution using the five-step process:1. **Formula:** Ohm's Law states V = IR, where V is voltage, I is current, and R is resistance. We need to rearrange this to solve for resistance (R): R = V/I2. **Known Values:** * V (Voltage) = 60 V * I (Current) = 0.7 A3. **Substitution:** Substitute the known values into the formula: R = 60 V / 0.7 A4. **Calculation:** Perform the division: R ≈ 85.7142857 Ω5. **Answer:** Rounding to a reasonable number of significant figures (likely two based on the given values), the resistance of the bulb is approximately 86 Ω (ohms).

Question

12. Complete the following calculations, showing ALL UNITS AND ALL FIVE STEPS. a. A light bulb passes through a current of 0.7 A when the potential difference across the bulb is 60 V. What is the resistance of the bulb in ohms?

Solution

Answer