If an individual with the genotype AabbCC is crossed with an individual with the genotype aaBBCC , what is the phenotype ratio?

Since we're dealing with a simple dominance inheritance pattern, let's break down the genotypes and possible gametes:* **Individual 1 (AabbCC):** Can produce two types of gametes: AbC and abC.* **Individual 2 (aaBBCC):** Can produce only one type of gamete: aBC.Now, let's create a Punnett square (or consider the combinations):| | AbC | abC || :---- | :--- | :--- || **aBC** | AaBbCC | aaBbCC |From the Punnett square, we see two possible genotypes:* **AaBbCC:** Displays the dominant phenotypes for A, B, and C.* **aaBbCC:** Displays the recessive phenotype for A, and the dominant phenotypes for B and C.Since the question asks for the *phenotype* ratio, and we're assuming simple dominance (where the presence of even one dominant allele expresses the dominant trait), both genotypes will express the dominant C trait. The difference lies in the A and B traits.* **AaBbCC:** Dominant A, Dominant B* **aaBbCC:** Recessive A, Dominant BTherefore, the phenotypic ratio is 1:1. Half the offspring will express the dominant A phenotype, and the other half will express the recessive A phenotype. All offspring will express the dominant B and C phenotypes.