5. A solid rectangle has the following dimensions.60.0 cm long, 10.0 cm wide and 500 cm deep. What is the volume of that rectangle in both cm^3 and mL? If that rectangle had a mass of 26 .88 kg, what is the density of that substance? Also, what is the identity of this substance?

Question

5. A solid rectangle has the following dimensions.60.0 cm long, 10.0 cm wide and 500 cm deep. What is the volume of that rectangle in both cm^3 and mL? If that rectangle had a mass of 26 .88 kg, what is the density of that substance? Also, what is the identity of this substance?

Answer 1

Here's the solution:**1. Calculating the Volume:*** **Formula:** Volume of a rectangular solid = length × width × depth* **Calculation:** Volume = 60.0 cm × 10.0 cm × 500 cm = 300,000 cm³* **Conversion to mL:** 1 cm³ = 1 mL, so the volume is also 300,000 mL**2. Calculating the Density:*** **Formula:** Density = mass / volume* **Mass Conversion:** First, convert the mass from kg to g: 26.88 kg × 1000 g/kg = 26,880 g* **Calculation:** Density = 26,880 g / 300,000 cm³ = 0.0896 g/cm³**3. Identifying the Substance:**A density of 0.0896 g/cm³ is very close to the density of paraffin wax, which is typically around 0.9 g/cm³. Given the potential for slight variations in density due to temperature and purity, the substance is likely **paraffin wax**.

Question

5. A solid rectangle has the following dimensions.60.0 cm long, 10.0 cm wide and 500 cm deep. What is the volume of that rectangle in both cm^3 and mL? If that rectangle had a mass of 26 .88 kg, what is the density of that substance? Also, what is the identity of this substance?

Solution

Answer