Question 8 A 100 N for is applied to move a crate 25 m which encounters 37 N of friction. What is the negative amount of work done in joules? square 1 pts

The work done by friction is given by the formula:Work = Force x Distance x cos(theta)Where:* Force is the frictional force (37 N)* Distance is the distance the crate moves (25 m)* Theta is the angle between the force and the direction of motion. Since friction always opposes motion, the angle is 180 degrees.cos(180°) = -1Therefore, the work done by friction is:Work = (37 N) * (25 m) * (-1) = -925 JoulesSo the negative amount of work done is Joules.