4. Fill out the table for the circuit diagramed at the right. }(c) Circuit Position & Voltage (V) & Current (A) & Resistance (Omega) 1 & & & 2.00 2 & & & 5.00 3 & & & 10.0 Total & 9.00 & &

#Explanation#The table provided corresponds to a circuit with three resistors in series. The total voltage across the circuit is given as 9V. In a series circuit, the total resistance is the sum of the individual resistances, and the current through each component is the same.The total resistance ( ) can be calculated using the formula: Substituting the given values: The current ( ) in a circuit can be calculated using Ohm's law, which states: Substituting the total voltage (9V) and the total resistance (17Ω): This current is the same throughout the circuit because it is a series circuit. The voltage across each resistor can also be calculated using Ohm's law. For each resistor: Substituting the current (0.53A) and the resistance for each resistor:For the 2Ω resistor: For the 5Ω resistor: For the 10Ω resistor: #Answer#The completed table is:\begin{array}{|c|c|c|c|}\hline\ \begin{array}{c}\ Circuit\ \\Position\end{array} & Voltage (V) & \begin{array}{c}\ Current\ \\(A)\end{array} & \begin{array}{c}\ Resistance\ \\\ (\Omega)\ \end{array} \\\hline 1 & 1.06 & 0.53 & 2.00 \\\hline 2 & 2.65 & 0.53 & 5.00 \\\hline 3 & 5.29 & 0.53 & 10.0 \\\hline Total & 9.00 & 0.53 & 17.0 \\\hline\end{array}