s traveling at 21.0m/s It slows to a stop at a constant rate over 5.00s How far does t during those 5.00 seconds before it stops? om 105 m 52.5 m

Here's how to solve this problem:**1. Identify the knowns:*** Initial velocity (v₀) = 21.0 m/s* Final velocity (vf) = 0 m/s (since it comes to a stop)* Time (t) = 5.00 s**2. Determine the appropriate equation:**Since we have constant acceleration (or deceleration in this case), we can use one of the kinematic equations. The most suitable equation is:d = (v₀ + vf) * t / 2where 'd' is the distance traveled.**3. Plug in the values and solve:**d = (21.0 m/s + 0 m/s) * 5.00 s / 2d = (21.0 m/s) * 2.50 sd = 52.5 m**Answer:** The car travels 52.5 m before stopping.