Question
60. Two particles, each with charge +4.2mu C, exhibit a repulsive force of 0 .25 N. Calculate the distance that separates the particles.7.2) 111
Solution
4.4
(70 Votes)
Brayden
Master · Tutor for 5 years
Answer
Here's how to calculate the distance between the two charged particles:**1. Formula:**We'll use Coulomb's Law, which states:F = k * |q1 * q2| / r^2Where:* F is the force between the charges (0.25 N)* k is Coulomb's constant (approximately 8.99 x 10^9 N m²/C²)* q1 and q2 are the magnitudes of the charges (both 4.2 x 10^-6 C)* r is the distance between the charges (what we want to find)**2. Rearrange the formula to solve for r:**r = sqrt(k * |q1 * q2| / F)**3. Plug in the values:**r = sqrt((8.99 x 10^9 N m²/C²) * (4.2 x 10^-6 C) * (4.2 x 10^-6 C) / (0.25 N))**4. Calculate:**r = sqrt(0.635028) mr ≈ 0.797 m or approximately 80 cm**Therefore, the distance separating the particles is approximately 0.80 meters.**