5th floor of a building you see the top of another taller elevation of 65^circ and the base of t hat building at an angl of depr ession of 37^circ apart,how tall is the other building Round your fin answer to one decimal place.

## Step 1: Visualizing the Problem### We can represent the situation with a right triangle where the height of the observed building above the observer's window is one leg, the horizontal distance between the buildings is the other leg, and the line of sight to the top of the building is the hypotenuse. Another right triangle is formed with the observer's window, the base of the observed building, and the horizontal distance between the buildings. The angle of depression to the base of the building is equal to the angle of elevation from the base of the building to the observer's window.## Step 2: Calculating the Horizontal Distance### Let 'h' be the height of the observed building above the observer's window and 'd' be the horizontal distance between the buildings. We have and , assuming each floor has a standard height. Let's assume a standard floor height of 3 meters, so the observer is 15 meters high. Then, meters.## Step 3: Calculating the Height Above the Observer### Using the horizontal distance calculated in the previous step, we can find 'h': meters.## Step 4: Calculating the Total Height### The total height of the building is the height above the observer plus the height of the observer's window: meters.## Step 5: Rounding to One Decimal Place### Rounding the total height to one decimal place gives 57.7 meters.