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(2.07kPa-y_(i))/(2.07kPa-1.93kPa)=(18.0^circ C-17.6^circ C)/(18.0^circ )C-17.0^(circ C)

Question

(2.07kPa-y_(i))/(2.07kPa-1.93kPa)=(18.0^circ C-17.6^circ C)/(18.0^circ )C-17.0^(circ C)

Solution

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Answer

Here's how to solve for yi:1. **Simplify the fractions:** 2. **Further simplify the right side:** 3. **Multiply both sides by 0.14 kPa:** 4. **Calculate the right side:** 5. **Isolate yi:** 6. **Calculate yi:** Therefore,