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A Gold Medal Run Olympian Donovan Bailey Took Gold for His 1996 Run in the 100 M Event. He Completed the Run in Just 9.84 S. From the

Question

A Gold Medal Run Olympian Donovan Bailey took gold for his 1996 run in the 100 m event. He completed the run in just 9.84 s. From the starting blocks he accelerated at 2.34m/s^2 for 6.5 seconds. He then held this constant speed until the finish line. It was a proud Canadian moment. During Donovan Bailey's Gold medal run, what was his maximum velocity during the race? 15.2m/s 10.2m/s 18.3m/s 12.1m/s

Solution

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Answer

Here's how to calculate Donovan Bailey's maximum velocity:* **Understand the problem:** The problem states that Bailey accelerated for 6.5 seconds and then maintained a constant velocity. This means his maximum velocity was reached at the end of the acceleration period.* **Use the correct formula:** We can use the following equation of motion to find his final velocity after the acceleration period: v = u + at Where: * v = final velocity (what we want to find) * u = initial velocity (which is 0 m/s since he starts from rest) * a = acceleration (2.34 m/s²) * t = time (6.5 s)* **Calculate:** v = 0 + (2.34 m/s² * 6.5 s) v = 15.21 m/s* **Answer:** His maximum velocity during the race was approximately 15.2 m/s. Therefore, the correct answer is .