5. A bungee jumper is falling at a velocity of 25m/s [down] when the bungee cord just starts to stretch. After the cord stretches for 2.5 s,the velocity is 11m/s [down]. Assume that the acceleration is constant. a. What is the acceleration of the jumper?

Question

5. A bungee jumper is falling at a velocity of 25m/s [down] when the bungee cord just starts to stretch. After the cord stretches for 2.5 s,the velocity is 11m/s [down]. Assume that the acceleration is constant. a. What is the acceleration of the jumper?

Answer 1

**a. What is the acceleration of the jumper?**Here's how to calculate the acceleration:1. **Identify the knowns:*** Initial velocity (vᵢ) = 25 m/s [down] (We'll use positive values for downward motion)* Final velocity (vₙ) = 11 m/s [down]* Time interval (Δt) = 2.5 s2. **Choose the appropriate equation:** We can use the following equation of motion: vₙ = vᵢ + aΔt where 'a' is the acceleration.3. **Rearrange the equation to solve for acceleration (a):** a = (vₙ - vᵢ) / Δt4. **Substitute the known values and solve:** a = (11 m/s - 25 m/s) / 2.5 s a = -14 m/s / 2.5 s a = -5.6 m/s²Since we designated downwards as positive, the negative sign indicates the acceleration is *upwards*.**Answer:** The acceleration of the jumper is 5.6 m/s² [up].

Question

5. A bungee jumper is falling at a velocity of 25m/s [down] when the bungee cord just starts to stretch. After the cord stretches for 2.5 s,the velocity is 11m/s [down]. Assume that the acceleration is constant. a. What is the acceleration of the jumper?

Solution

Answer