3. Yves Trough, a French Canadian fur trader, took 2 hours to paddle his canoe 24 km downstream to the Hudson's Bay trading post.The return trip against the current took 3 hours. Find the speed of the canoe in still water and the speed of the current.

Let 'c' be the speed of the canoe in still water (km/h) and 'w' be the speed of the current (km/h).**Downstream:*** The speed of the canoe going downstream is the sum of the canoe's speed and the current's speed (c + w).* The distance traveled downstream is 24 km.* The time taken downstream is 2 hours.* We can use the formula: distance = speed × timeTherefore, 24 = (c + w) × 2 ---> Equation (1)**Upstream:*** The speed of the canoe going upstream is the difference between the canoe's speed and the current's speed (c - w).* The distance traveled upstream is also 24 km (same distance back).* The time taken upstream is 4 hours.* Using the same formula: distance = speed × timeTherefore, 24 = (c - w) × 4 ---> Equation (2)Now we have a system of two equations with two variables:Equation (1): 2c + 2w = 24Equation (2): 4c - 4w = 24We can simplify these equations:Equation (1): c + w = 12 (Divide both sides by 2)Equation (2): c - w = 6 (Divide both sides by 4)Now we can solve for 'c' and 'w' using either substitution or elimination. Here's the elimination method:Add Equation (1) and Equation (2):(c + w) + (c - w) = 12 + 62c = 18c = 9Now substitute the value of 'c' (9) back into either Equation (1) or (2). Let's use Equation (1):9 + w = 12w = 12 - 9w = 3Therefore, the speed of the canoe in still water is km/h, and the speed of the current is km/h.