The absolute minimum value of f(x)=3x^2-12x+5 on the interval [0,3] ()5 -4 7 3 -7

## Step 1: Find the derivative of the function### To find the critical points, we need to take the derivative of the function . The derivative is .## Step 2: Find the critical points### Set the derivative equal to zero and solve for : . This critical point lies within the interval .## Step 3: Evaluate the function at the critical point and endpoints### Evaluate the function at the critical point and the endpoints and : ## Step 4: Determine the absolute minimum### Comparing the values , , and , the absolute minimum value is .