17. Four resistors are placed in series in a circuit Their resistances are R_(1)=10.1Omega ,R_(2)=19.8Omega R_(3)=50.3Omega ,R_(4)=25.4Omega . What is the total resistance of the circuit? a. 95.5Omega b. 108Omega C. 80.2Omega d. 106Omega

Question

17. Four resistors are placed in series in a circuit Their resistances are R_(1)=10.1Omega ,R_(2)=19.8Omega R_(3)=50.3Omega ,R_(4)=25.4Omega . What is the total resistance of the circuit? a. 95.5Omega b. 108Omega C. 80.2Omega d. 106Omega

Answer 1

The total resistance of resistors in series is simply the sum of their individual resistances.* R_total = R1 + R2 + R3 + R4* R_total = 10.1 Ω + 19.8 Ω + 50.3 Ω + 25.4 Ω* R_total = 105.6 ΩSince 105.6 Ω is closest to 106 Ω, the correct answer is **d. 106 Ω**. The slight difference is likely due to rounding in the provided answer choices.

Question

17. Four resistors are placed in series in a circuit Their resistances are R_(1)=10.1Omega ,R_(2)=19.8Omega R_(3)=50.3Omega ,R_(4)=25.4Omega . What is the total resistance of the circuit? a. 95.5Omega b. 108Omega C. 80.2Omega d. 106Omega

Solution

Answer