At a baseball game the batter hits the ball straight up into the air at a speed of 38.0m/s Numeric Response 2.1.20 seconds after the batter hits the ball, it will be moving at a speed of underline ( )m/s (Record your answer in the numerical-response section on the answer sheet.)

Question

At a baseball game the batter hits the ball straight up into the air at a speed of 38.0m/s Numeric Response 2.1.20 seconds after the batter hits the ball, it will be moving at a speed of underline ( )m/s (Record your answer in the numerical-response section on the answer sheet.)

Answer 1

Here's how to solve this problem:**Understanding the Problem**The baseball is subject to gravity, which causes it to decelerate as it rises. We need to calculate its speed after a specific time.**Relevant Equations*** v = u + at Where:* v = final velocity (what we want to find)* u = initial velocity (38.0 m/s)* a = acceleration due to gravity (-9.81 m/s², negative since it acts downwards)* t = time (2.1 seconds)**Calculations**1. Substitute the known values into the equation: v = 38.0 m/s + (-9.81 m/s²)(2.1 s)2. Calculate: v = 38.0 m/s - 20.601 m/s v = 17.399 m/s3. Round to the appropriate number of significant figures (likely three, based on the given data): v ≈ 17.4 m/s**Answer**The ball will be moving at a speed of approximately 17.4 m/s after 2.1 seconds. Therefore, you would fill in `17.4` on the numerical response section.

Question

At a baseball game the batter hits the ball straight up into the air at a speed of 38.0m/s Numeric Response 2.1.20 seconds after the batter hits the ball, it will be moving at a speed of underline ( )m/s (Record your answer in the numerical-response section on the answer sheet.)

Solution

Answer