Question
This graph describes Mina's displacement from her house during a walk on a straight path. What is the average velocity on the interval 4<t<18 4leqslant tleqslant 18 800. Displacement (m) 700 800 500 400 300 200 100 Time (min) n 12
Solution
4.3
(276 Votes)
Gabriella
Master ยท Tutor for 5 years
Answer
To calculate the **average velocity** of Mina on the interval
, we use the formula for average velocity:
where:-
is the change in displacement (final displacement - initial displacement),-
is the change in time (final time - initial time).### Step 1: Identify the displacement at
and
From the graph:- At
, the displacement is \( x(4) = 700 \, \text{m} \).- At
, the displacement is \( x(18) = 300 \, \text{m} \).### Step 2: Calculate
and
- \( \Delta x = x(18) - x(4) = 300 - 700 = -400 \, \text{m} \),-
.### Step 3: Compute the average velocitySubstitute into the formula:
### Final Answer:The average velocity on the interval
is approximately: