24. Suppose a 1000 -kg car collides with a tree. Its speed changes from 6m/s to 0m/s. The impuls on the car is (0.5 Points) [4 positive negative 25. A baseball catcher holds his arm straight out to catch a ball. The change in momentum on his glove is 5kgcdot m/s. The ball stops in 0.01 seconds.The initial speed of the ball is 30m/s. The force of impact is (1 Point) [4 3N 6N 150 N 500 N

Question

24. Suppose a 1000 -kg car collides with a tree. Its speed changes from 6m/s to 0m/s. The impuls on the car is (0.5 Points) [4 positive negative 25. A baseball catcher holds his arm straight out to catch a ball. The change in momentum on his glove is 5kgcdot m/s. The ball stops in 0.01 seconds.The initial speed of the ball is 30m/s. The force of impact is (1 Point) [4 3N 6N 150 N 500 N

Answer 1

**24.**The impulse on the car is calculated as the change in momentum:Impulse = Δp = mΔv = m(v_final - v_initial)Where:* m = mass of the car = 1000 kg* v_final = final velocity = 0 m/s* v_initial = initial velocity = 6 m/sImpulse = 1000 kg * (0 m/s - 6 m/s) = -6000 kg⋅m/sSince the impulse is negative, this indicates that the force acting on the car is in the opposite direction of its initial motion.**Answer:** negative**25.**The force of impact can be calculated using the impulse-momentum theorem:Impulse = Δp = FΔtWhere:* Δp = change in momentum = 5 kg⋅m/s* Δt = time interval = 0.01 s* F = force of impactWe can rearrange the equation to solve for F:F = Δp / ΔtF = (5 kg⋅m/s) / (0.01 s) = 500 N**Answer:** 500 N

Question

Solution

Answer