3) A bicycle wheel has an initial angular velocity of 1.50rad/s. If its angular acceleration is constant and equal to 0.200rad/s^2 what is its angular velocity after it has turned through 3.50 revolutions. 3.32rad/s

Here's how to solve this problem:**1. Convert revolutions to radians:*** One revolution is equal to 2π radians.* 3.50 revolutions * 2π radians/revolution = 7π radians**2. Use the following rotational kinematics equation:**ωf2 = ωi2 + 2αθWhere:* ωf is the final angular velocity (what we want to find)* ωi is the initial angular velocity (1.50 rad/s)* α is the angular acceleration (0.200 rad/s²)* θ is the angular displacement (7π radians)**3. Substitute the known values and solve for ωf:**ωf2 = (1.50 rad/s)2 + 2 * (0.200 rad/s²) * (7π radians)ωf2 = 2.25 rad²/s² + 8.796 rad²/s²ωf2 = 11.046 rad²/s²ωf = √(11.046 rad²/s²)ωf ≈ 3.32 rad/sTherefore, the final angular velocity after the bicycle wheel has turned through 3.50 revolutions is approximately . The provided answer is correct.