MCF3M CPT Part 1 - Chapters 5,7,8 1. In Delta ABC:angle B=90^circ ,angle C=33^circ ,b=4.9cm Draw a sketch of the triangle and solve for all side lengths and angles.

Here's how to solve the triangle:**1. Sketch the Triangle:**Draw a right-angled triangle. Label the right angle as B. Label angle C as 33°. Label the hypotenuse (opposite the right angle) as 'b' and indicate its length as 4.9 cm. Label the side opposite angle A as 'a' and the side opposite angle C as 'c'.**2. Find Angle A:**Since the sum of angles in a triangle is 180°, we have:A + B + C = 180°A + 90° + 33° = 180°A = 180° - 90° - 33°A = 57°**3. Find side 'c' (adjacent to angle C):**We can use the cosine ratio:cos(C) = adjacent/hypotenusecos(33°) = c/4.9 cmc = 4.9 cm * cos(33°)c ≈ 4.1 cm (rounded to one decimal place)**4. Find side 'a' (opposite angle A):**We can use the sine ratio:sin(C) = opposite/hypotenusesin(33°) = a/4.9 cma = 4.9 cm * sin(33°)a ≈ 2.7 cm (rounded to one decimal place)**Solution Summary:*** Angle A = 57°* Angle B = 90°* Angle C = 33°* Side a ≈ 2.7 cm* Side b = 4.9 cm* Side c ≈ 4.1 cm