1. Write balanced nuclear equations for the following: A.the alpha decay of lead -208

. Alpha decay involves the emission of an alpha particle, which is a helium nucleus (₂⁴He). When lead-208 undergoes alpha decay, it loses 2 protons and 2 neutrons.* **Start with the parent isotope:** ²⁰⁸₈₂Pb* **Subtract the alpha particle:** ²⁰⁸₈₂Pb - ₂⁴He* **Calculate the daughter isotope:** ²⁰⁴₈₀Hg* **The balanced nuclear equation is:**²⁰⁸₈₂Pb → ²⁰⁴₈₀Hg + ₂⁴He