40. A nuclear power plant transmits 6.0 kA through a transmission line with a resistance of 0.50Omega . If there is a 0.70% loss of power due to transmission how much power does the nuclear plant generate? (13.6) I'm

Question

40. A nuclear power plant transmits 6.0 kA through a transmission line with a resistance of 0.50Omega . If there is a 0.70% loss of power due to transmission how much power does the nuclear plant generate? (13.6) I'm

Answer 1

Here's how to solve this problem:1. **Calculate the power loss in the transmission line:**Power loss (P_loss) can be calculated using the formula P_loss = I² * R, where I is the current and R is the resistance.* P_loss = (6000 A)² * 0.50 Ω* P_loss = 18,000,000 W = 18 MW2. **Determine the power delivered:**We know that 0.70% of the total power generated is lost in transmission. This means the 18 MW represents 0.70% of the total power. Let P_total be the total power generated.* 0.0070 * P_total = 18 MW3. **Calculate the total power generated:**Solve for P_total:* P_total = 18 MW / 0.0070* P_total ≈ 2571.43 MWTherefore, the nuclear power plant generates approximately 2571.43 MW of power.

Question

40. A nuclear power plant transmits 6.0 kA through a transmission line with a resistance of 0.50Omega . If there is a 0.70% loss of power due to transmission how much power does the nuclear plant generate? (13.6) I'm

Solution

Answer