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PRC4A17-A1-7-2 -11 The Coefficient of Friction Between a Block and a Horizontal Surface Is 0.290 Determine the Mass of the Block If a

Question

PRC4A17-A1-7-2 -11 The coefficient of friction between a block and a horizontal surface is 0.290 Determine the mass of the block if a force of 950.000 N is required to keep it sliding alcing the surface. square A

Solution

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Harvey Master · Tutor for 5 years

Answer

Here's how to solve this problem:**1. Understand the concept of friction:**The force of friction (Ff) acting on an object sliding on a surface is given by:Ff = μ * NWhere:* μ is the coefficient of friction* N is the normal force (the force perpendicular to the surface)**2. Determine the normal force:**Since the block is on a horizontal surface, the normal force (N) is equal to the weight (W) of the block:N = W = m * gWhere:* m is the mass of the block* g is the acceleration due to gravity (approximately 9.8 m/s²)**3. Relate the applied force to the force of friction:**The problem states that a force of 950 N is required to *keep* the block sliding. This means the applied force is equal to the force of friction:Fapplied = Ff**4. Solve for the mass:**Now we can put everything together:Fapplied = Ff = μ * N = μ * m * gWe are given:* Fapplied = 950 N* μ = 0.290* g = 9.8 m/s²We need to solve for m:m = Fapplied / (μ * g)m = 950 N / (0.290 * 9.8 m/s²)m ≈ 335.6 kg**Answer:**The mass of the block is approximately 335.6 kg.