17. A projectile is fired aran angle of 35^circ relative to the horizontal (upwards) with a speed of 20m/s (linore air resistance,Calculate the a. horizontal componen of the projectile's initial velocity, [16m/s] b. vertical component of the projectile's initial velocity. [11m/s] c. time the projectile is in the air. [2.] I d. horizontal distance the projectile travels (Le, it range), [3B m]

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17. A projectile is fired aran angle of 35^circ relative to the horizontal (upwards) with a speed of 20m/s (linore air resistance,Calculate the a. horizontal componen of the projectile's initial velocity, [16m/s] b. vertical component of the projectile's initial velocity. [11m/s] c. time the projectile is in the air. [2.] I d. horizontal distance the projectile travels (Le, it range), [3B m]

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Here's the solution:**a. Horizontal component of initial velocity:*** The horizontal component (vₓ) is found using the cosine of the launch angle: vₓ = v * cos(θ)* vₓ = 20 m/s * cos(35°) * vₓ ≈ 16.38 m/s ≈ **16 m/s** (rounded to two significant figures as per the provided answer)**b. Vertical component of initial velocity:*** The vertical component (vᵧ) is found using the sine of the launch angle: vᵧ = v * sin(θ)* vᵧ = 20 m/s * sin(35°)* vᵧ ≈ 11.47 m/s ≈ **11 m/s** (rounded to two significant figures)**c. Time the projectile is in the air:*** The time of flight (t) can be found using the vertical component of the velocity and the acceleration due to gravity (g = 9.8 m/s²). The time it takes to reach the highest point is equal to the time it takes to fall back down. We can use the following equation: v_f = v_i - gt, where v_f is the final vertical velocity (0 m/s at the highest point), and v_i is the initial vertical velocity.* 0 = vᵧ - gt* t = vᵧ / g* t = 11.47 m/s / 9.8 m/s²* t ≈ 1.17 s This is the time to reach the highest point. The total time in the air is twice this:* Total time = 2 * t ≈ 2 * 1.17 s ≈ 2.34 s ≈ **2.3 s** (The provided answer of 2.1s seems to have used a rounded value of 11 m/s for the vertical velocity. Using the more precise 11.47 m/s gives a more accurate answer of 2.3s)**d. Horizontal distance the projectile travels (Range):*** The range (R) is the horizontal distance traveled and is calculated using the horizontal velocity and the total time of flight: R = vₓ * t* R ≈ 16.38 m/s * 2.34 s* R ≈ 38.3 m ≈ **38 m** (The provided answer of 38m is consistent with using the slightly less precise values from earlier calculations. If we use the more precise values, we get a range closer to 38m).

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