1. 18 C of charge pass a certain point in a conductor in 2.5 s a) What is the current in the wire? b) How many electrons have passed that point in the wire in 2.5 s? a) exists =(Q)/(t)=(18C)/(2.55)=7.24

Question

1. 18 C of charge pass a certain point in a conductor in 2.5 s a) What is the current in the wire? b) How many electrons have passed that point in the wire in 2.5 s? a) exists =(Q)/(t)=(18C)/(2.55)=7.24

Answer 1

1. 18 C of charge pass a certain point in a conductor in 2.5 sa) What is the current in the wire?Current (I) is defined as the rate of flow of charge (Q) with respect to time (t). The formula is:I = Q / tWhere:* I is the current in Amperes (A)* Q is the charge in Coulombs (C)* t is the time in seconds (s)In this case, Q = 18 C and t = 2.5 s. Therefore:I = 18 C / 2.5 s = 7.2 ASo, the current in the wire is 7.2 Amperes.b) How many electrons have passed that point in the wire in 2.5 s?We know that the charge of a single electron (e) is approximately -1.6 x 10⁻¹⁹ C. To find the number of electrons (n) that have passed a point, we can use the following formula:Q = n * eWhere:* Q is the total charge in Coulombs (C)* n is the number of electrons* e is the elementary charge (1.6 x 10⁻¹⁹ C)We can rearrange the formula to solve for n:n = Q / eSubstituting the values:n = 18 C / (1.6 x 10⁻¹⁹ C) n = 1.125 x 10²⁰ electronsSo, approximately 1.125 x 10²⁰ electrons have passed that point in the wire in 2.5 seconds.

Question

1. 18 C of charge pass a certain point in a conductor in 2.5 s a) What is the current in the wire? b) How many electrons have passed that point in the wire in 2.5 s? a) exists =(Q)/(t)=(18C)/(2.55)=7.24

Solution

Answer