MERIC RESPONSE QUESTIONS 29-30=Total/4points ne the temperature change of 300 grams of water when 1000 joules of energy is ad __ C_(water)=4.19J/g^circ C rd your three-digit answer on the numerical-response answer sheet provided.)

Question

MERIC RESPONSE QUESTIONS 29-30=Total/4points ne the temperature change of 300 grams of water when 1000 joules of energy is ad __ C_(water)=4.19J/g^circ C rd your three-digit answer on the numerical-response answer sheet provided.)

Answer 1

Here's how to solve this problem:1. **Recall the formula that relates heat energy (Q), mass (m), specific heat capacity (c), and temperature change (ΔT):** Q = mcΔT2. **Rearrange the formula to solve for the temperature change (ΔT):** ΔT = Q / (mc)3. **Plug in the given values:** * Q = 1000 J * m = 300 g * c = 4.19 J/g°C ΔT = 1000 J / (300 g * 4.19 J/g°C)4. **Calculate the temperature change:** ΔT ≈ 0.796 °C5. **Round to the nearest hundredth:** ΔT ≈ 0.80 °CTherefore, the temperature change of the water is approximately 0.80°C. Since the question asks for a three-digit answer, you would enter *0.80* or *080* on the numerical response sheet.

Question

MERIC RESPONSE QUESTIONS 29-30=Total/4points ne the temperature change of 300 grams of water when 1000 joules of energy is ad __ __ __ C_(water)=4.19J/g^circ C rd your three-digit answer on the numerical-response answer sheet provided.)

Solution

Answer

MERIC RESPONSE QUESTIONS 29-30=Total/4points ne the temperature change of 300 grams of water when 1000 joules of energy is ad __ C_(water)=4.19J/g^circ C rd your three-digit answer on the numerical-response answer sheet provided.)