A 800kg car, traveling 16m/s to the right collides with a 3000kg semi truck initially at rest. After the 07s collision, the semi truck ends up moving 5.8m/s m/s right. vert Jvert =square unit before collision: P_(car)=square unit P_(truck)=square unit after collision: P_(car)=square unit P_(truck)=square unit What direction did the car move after the collision? square How fast did the car move after the collision? square square v What was the magnitude of the average impact force? square square

Here's the solution:**1. Impulse:**The impulse ( ) is the change in momentum of the truck (since it started from rest).* Impulse = change in momentum of the truck* * * ** kg*m/s****2. Momentum Before Collision:*** * ** kg*m/s**** kg*m/s****3. Momentum After Collision:*** * To find the car's momentum after the collision, we use the principle of conservation of momentum: * Total momentum before = Total momentum after * * * ** kg*m/s**** kg*m/s****4. Car's Direction After Collision:**The negative sign on the car's momentum indicates it's moving in the opposite direction to its initial motion.**Left****5. Car's Speed After Collision:*** * * * The speed is the absolute value of the velocity.**5.75 m/s****6. Magnitude of Average Impact Force:*** Impulse = Force * time* * * **24857.14 N** (or approximately 24900 N depending on significant figures)