14. A high-speed windmill can utilize a maximum wind power of 6.53times 10^3 W. If the windmill turned a generator that was only 27.0% efficient, the actual electrical power output is a.bctimes 10^dW The values of a b, c and d are and (Record your answer in the numerical-response section below.) Your answer: square square square square

Question

14. A high-speed windmill can utilize a maximum wind power of 6.53times 10^3 W. If the windmill turned a generator that was only 27.0% efficient, the actual electrical power output is a.bctimes 10^dW The values of a b, c and d are and (Record your answer in the numerical-response section below.) Your answer: square square square square

Answer 1

To find the actual electrical power output of the windmill, we need to calculate 27.0% of the maximum wind power it can utilize.Given:- Maximum wind power =

W- Efficiency of the generator = 27.0%The actual electrical power output is calculated as follows:

Now, express this in the form

:-

-

Therefore, the values of

,

, and

are 1, 7, 6, and 3 respectively.Your answer:

Question

Solution

Answer