Rhea has 10 basketballs each of a different colour. She only has time to shoot 5 hoops before going to bed.How many different arrangements can the balls be thrown into the hoops? 1 120 square 2 square 3 30,24 o

Question

Rhea has 10 basketballs each of a different colour. She only has time to shoot 5 hoops before going to bed.How many different arrangements can the balls be thrown into the hoops? 1 120 square 2 square 3 30,24 o

Answer 1

Here's how to solve this problem:**Understanding the Problem**Rhea is choosing 5 basketballs out of 10, and the order in which she shoots them matters (since the question asks about *arrangements*). This is a permutation problem.**Formula**The formula for permutations is:P(n, r) = n! / (n - r)!Where:* n = total number of items (10 basketballs)* r = number of items being chosen (5 basketballs)**Calculation**P(10, 5) = 10! / (10 - 5)! = 10! / 5! = (10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1) / (5 * 4 * 3 * 2 * 1) = 10 * 9 * 8 * 7 * 6 = 30,240**Answer**The correct answer is 30,240. So, option 3 is correct.

Question

Rhea has 10 basketballs each of a different colour. She only has time to shoot 5 hoops before going to bed.How many different arrangements can the balls be thrown into the hoops? 1 120 square 2 square 3 30,24 o

Solution

Answer