Question 31 (1 point) PRC4A17-A1-8 -3-7 A uniform bar 1.1 metres in length and having a cross sectional area of 11.5cm^2 is subject to a loading of 9000 Newtons Calculate the stress produced in kPa. square A I

Question

Question 31 (1 point) PRC4A17-A1-8 -3-7 A uniform bar 1.1 metres in length and having a cross sectional area of 11.5cm^2 is subject to a loading of 9000 Newtons Calculate the stress produced in kPa. square A I

Answer 1

Here's how to calculate the stress:1. **Convert the area to square meters:** 11.5 cm² * (1 m / 100 cm)² = 0.00115 m²2. **Calculate the stress:** Stress = Force / Area Stress = 9000 N / 0.00115 m² Stress = 7,826,086.96 Pa3. **Convert to kPa:** Stress = 7,826,086.96 Pa * (1 kPa / 1000 Pa) Stress ≈ 7826.1 kPaTherefore, the stress produced is approximately **7826.1 kPa**.

Question

Question 31 (1 point) PRC4A17-A1-8 -3-7 A uniform bar 1.1 metres in length and having a cross sectional area of 11.5cm^2 is subject to a loading of 9000 Newtons Calculate the stress produced in kPa. square A I

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