Find the force in newtons needed to slow a 2500 kg truck from 20m/s to 10m/s in 100m. Hint:keep in mind the truck is slowing down.

Here's how to find the force needed to slow the truck:1. **Calculate the change in velocity (Δv):** Δv = Final velocity - Initial velocity Δv = 10 m/s - 20 m/s = -10 m/s (The negative sign indicates deceleration)2. **Calculate the acceleration (a):** We can use the following equation of motion: v² = u² + 2as Where: * v = final velocity (10 m/s) * u = initial velocity (20 m/s) * a = acceleration (what we want to find) * s = distance (100 m) Rearranging the equation to solve for 'a': a = (v² - u²) / 2s a = (10² - 20²) / (2 * 100) a = (100 - 400) / 200 a = -300 / 200 a = -1.5 m/s² (Again, the negative sign indicates deceleration)3. **Calculate the force (F):** Use Newton's second law of motion: F = ma Where: * F = force (what we want to find) * m = mass (2500 kg) * a = acceleration (-1.5 m/s²) F = 2500 kg * (-1.5 m/s²) F = -3750 NTherefore, the force needed to slow the truck is 3750 N. The negative sign indicates that the force is acting opposite to the direction of motion (i.e., it's a braking force).