2. A ball is thrown upwards. If the ball was thrown with an initial velocity of 20.0m/s[up] , how long does it take to reach the maximum height?

Here's how to solve this problem:**1. Understand the concept:**At the maximum height, the ball's velocity is momentarily zero before it starts falling back down. We can use this fact to solve for the time.**2. Identify the knowns:*** Initial velocity (v₀) = +20.0 m/s (positive because it's upwards)* Final velocity (v) = 0 m/s (at the maximum height)* Acceleration (a) = -9.8 m/s² (due to gravity, downwards, hence negative)**3. Choose the right equation:**We can use the following kinematic equation:v = v₀ + at**4. Solve for time (t):*** Rearrange the equation to solve for t: t = (v - v₀) / a* Substitute the known values: t = (0 m/s - 20.0 m/s) / (-9.8 m/s²)* Calculate: t ≈ 2.04 s**Answer:** It takes approximately 2.04 seconds for the ball to reach its maximum height.