5) A flywheel whose angular acceleration is constant and equal to 2.50rad/s^2 rotates through an angle of 100 rad in 5 .00 s. What was the angular velocity of the flywheel at the beginning of the 5.00 s interval? 13.75rad/s

Question

5) A flywheel whose angular acceleration is constant and equal to 2.50rad/s^2 rotates through an angle of 100 rad in 5 .00 s. What was the angular velocity of the flywheel at the beginning of the 5.00 s interval? 13.75rad/s

Answer 1

Here's how to solve this problem:**1. Understand the given information:*** Angular acceleration (α) = 2.50 rad/s² (constant)* Angular displacement (θ) = 100 rad* Time (t) = 5.00 s**2. Identify the relevant equation:**We can use the following equation of rotational motion:θ = ω₀t + (1/2)αt²Where:* θ is the angular displacement* ω₀ is the initial angular velocity* α is the angular acceleration* t is the time**3. Solve for the initial angular velocity (ω₀):**We are given θ, α, and t, and we need to find ω₀. Let's rearrange the equation:ω₀ = (θ - (1/2)αt²) / t**4. Plug in the values and calculate:**ω₀ = (100 rad - (1/2)(2.50 rad/s²)(5.00 s)²) / (5.00 s)ω₀ = (100 rad - 31.25 rad) / 5.00 sω₀ = 68.75 rad / 5.00 sω₀ = 13.75 rad/s**Answer:**The angular velocity of the flywheel at the beginning of the 5.00 s interval was 13.75 rad/s.

Question

5) A flywheel whose angular acceleration is constant and equal to 2.50rad/s^2 rotates through an angle of 100 rad in 5 .00 s. What was the angular velocity of the flywheel at the beginning of the 5.00 s interval? 13.75rad/s

Solution

Answer