To divide a line segment in the ratio p:q (p,q are integers) a ray AX is drawn so thatdisplaystyle angle BAX is an acute angle and then mark points on ray AX at equal distances such that the minimum number of points is: (A) pq (B) p+q-1 (C) p+q (D) Greater of p and q

answer: c <br>draw the line $n$ number of points (equidistant)$n=p+q$At the nth point, join the end of line segment. At the beginning of line segment $A$ of line segment $AB$, draw a line parallel to that from $N$ cutting the original line segment $AB$$\therefore$ The minimum number of points required $=p+q$